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4x^2-80x+220=0
a = 4; b = -80; c = +220;
Δ = b2-4ac
Δ = -802-4·4·220
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-24\sqrt{5}}{2*4}=\frac{80-24\sqrt{5}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+24\sqrt{5}}{2*4}=\frac{80+24\sqrt{5}}{8} $
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